SOLUTION: PLEASE HELP ME I NEED HELP UNDERSTANDING HOW TO SOLVE THEM STEP BY STEP.... Problem #8 Which of the following investments is larger after 19 years? (a) $7500 is deposited

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: PLEASE HELP ME I NEED HELP UNDERSTANDING HOW TO SOLVE THEM STEP BY STEP.... Problem #8 Which of the following investments is larger after 19 years? (a) $7500 is deposited      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 86995: PLEASE HELP ME I NEED HELP UNDERSTANDING HOW TO SOLVE THEM STEP BY STEP....
Problem #8
Which of the following investments is larger after 19 years?
(a) $7500 is deposited annually and earns 4.5% interest compounded annually.
(b) $600 is deposited monthly and earns 4.5% interest compounded monthly.
Problem #9
Find monthly payment.
In order to purchase a home, a family borrows $26000 at 10.8 % for 15 yr. What is their monthly payment? Round the answer to the nearest cent.

Found 2 solutions by stanbon, jim_thompson5910:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Problem #8
Which of the following investments is larger after 19 years?
(a) $7500 is deposited annually and earns 4.5% interest compounded annually.
(b) $600 is deposited monthly and earns 4.5% interest compounded monthly.
-------
Compare their growth using compound interest formula and the the Future Value formula:
Compound Interest: FV = (principal)(1+r/n)^(nt)
FV = 7500(1+0.045/1)^(1*19)
-------
Future Value: FV = (periodic payment)[(1+i)^n -1]/i
where periodic payment = $600; n=12*19 ; i=0.045/12
======================
Problem #9
Find monthly payment.
In order to purchase a home, a family borrows $26000 at 10.8 % for 15 yr. What is their monthly payment? Round the answer to the nearest cent.
--------
Use this annuity formla:
balance = (loan amt)(1+i)^n - [P/i][(1+i)^n - 1]
You want the balance to be zero;
loan amt=26000
i=0.108/12
n=12*15
Solve for P=monthly payment.
--------
I get $292.26
============
Cheers,
Stan H.

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
#8
a)
Let p=7500, r=0.045, n=1, and t=19 and plug them into A=p%281%2Br%2Fn%29%5E%28n%2At%29

A=7500%281%2B0.045%2F1%29%5E%281%2A19%29 Start with the given expression
A=7500%281%2B0.045%29%5E%281%2A19%29 Divide 0.045 by 1 to get 0.045
A=7500%281%2B0.045%29%5E%2819%29 Multiply the exponents 1 and 19 to get 19
A=7500%281.045%29%5E%2819%29 Add 1 and 0.045 to get 1.045
A=7500%282.30786031084919%29 Raise 1.045 to the 19 th power to get 2.30786031084919
A=17308.9523313689 Multiply 7500 and 2.30786031084919 to get 17308.9523313689

So the return is $17,308.95

b)

Let p=600, r=0.045, n=12, and t=19 and plug them into A=p%281%2Br%2Fn%29%5E%28n%2At%29

A=600%281%2B0.045%2F12%29%5E%2812%2A19%29 Start with the given expression
A=600%281%2B0.00375%29%5E%2812%2A19%29 Divide 0.045 by 12 to get 0.00375
A=600%281%2B0.00375%29%5E%28228%29 Multiply the exponents 12 and 19 to get 228
A=600%281.00375%29%5E%28228%29 Add 1 and 0.00375 to get 1.00375
A=600%282.3476172358424%29 Raise 1.00375 to the 228 th power to get 2.3476172358424
A=1408.57034150544 Multiply 600 and 2.3476172358424 to get 1408.57034150544

So the return is $1408.57


So the $7,500 investment is larger after 19 years

----------------------------------------------------------------------
#9
To calculate the monthly payment, use this formula:

Monthly_Payment=%28P%2AR%2F%281-%281%2BR%29%5E%28-n%29%29%29 where P is the principal (i.e. the amount loaned out), R is the periodic interest rate (in decimal form) and n is the number of monthly payments

First lets calculate R:

R=10.8%2F%2812%2A100%29=0.009 To find the periodic interest rate, divide the APR (this is given as 10.8%) by the number of months in a year. Also divide the APR by 100 to convert the percentage to a decimal





Monthly_Payment=%2826000%2A0.009%2F%281-%281%2B0.009%29%5E%28-15%2A12%29%29%29 Start with the given expression

Monthly_Payment=%2826000%2A0.009%2F%281-%281.009%29%5E%28-15%2A12%29%29%29 Add 1%2B0.009 to get 1.009

Monthly_Payment=%2826000%2A0.009%2F%281-%281.009%29%5E%28-180%29%29%29 Multiply -15%2A12 to get -180

Monthly_Payment=%2826000%2A0.009%2F%281-%280.199337991176801%29%29%29 Raise 1.009 to the -180 power

Monthly_Payment=%2826000%2A0.009%2F%280.800662008823199%29%29%29 Subtract 1-0.199337991176801 to get 0.800662008823199

Monthly_Payment=%28234%2F%280.800662008823199%29%29%29 Multiply 26000%2A0.009 to get 234

Monthly_Payment=%28292.258153154949%29%29%29 Divide 234 by 0.800662008823199 to get 292.258153154949


So the monthly payment, rounded to the nearest cent, is roughly $292.26