SOLUTION: Determine the eccentricity of: {{{(y-5)^2 = 4(x-5)}}}

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Question 869892: Determine the eccentricity of:
%28y-5%29%5E2+=+4%28x-5%29
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

%28y-5%29%5E2+=+4%28x-5%29

The eccentricity of a parabola is the distance from the focus to any point on the graph 

divided by the distance from that same point on the graph to the directrix.

  Since this the same for a parabola, the eccentricity, e = 1.