SOLUTION: write the equation of the circle center (4,-2) containing the point (-4,13) can someone explain please

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Question 869730: write the equation of the circle
center (4,-2)
containing the point (-4,13)

can someone explain please

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
The segment with the endpoints (4,-2) and (-4,13) is a radius of the circle. Use the distance formula to get the value of the size of this radius.

Answer by MathTherapy(10555) About Me  (Show Source):
You can put this solution on YOUR website!
write the equation of the circle
center (4,-2)
containing the point (-4,13)

can someone explain please

STEP 1
Plug the center coordinate (h, k) and the point that the circle passes through into the center-radius form
of the equation of a circle, or in %28x+-+h%29%5E2+%2B+%28y+-+k%29%5E2+=+r%5E2. This will give you the value of the radius, squared, or r%5E2
STEP 2
Plug the center coordinate, and r%5E2 into the center-radius form of the equation of a circle and you will have the
equation of a circle, in center-radius form.
It's a s simple as that!!
You then do a check!!
If you need a complete and detailed solution, let me know!!
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