SOLUTION: How do I write (x-1)^2+5(y+2)^2=20 (an ellipse) in standard form? I know you divide by 20, but would it be (x-1)^2/20 + 5(y+2)^2/20=1? Whats the answer?

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: How do I write (x-1)^2+5(y+2)^2=20 (an ellipse) in standard form? I know you divide by 20, but would it be (x-1)^2/20 + 5(y+2)^2/20=1? Whats the answer?      Log On


   

Question 869723: How do I write (x-1)^2+5(y+2)^2=20 (an ellipse) in standard form? I know you divide by 20, but would it be (x-1)^2/20 + 5(y+2)^2/20=1? Whats the answer?
Found 2 solutions by jim_thompson5910, josgarithmetic:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
You would reduce 5(y+2)^2/20 to get (y+2)^2/4


So the final answer is %28%28x-1%29%5E2%29%2F%2820%29+%2B+%28%28y%2B2%29%5E2%29%2F%284%29+=+1

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Almost. Simplify the expression containing the y. This is only one more step.