Question 869685: cosx-2sinx^2+1=0
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! cosx-2sinx^2+1=0
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cos(x) - 2(1-cos^2(x))+1 = 0
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cos(x) -2 + 2cos^2(x) +1 = 0
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2cos^2(x) + x -1 = 0
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Factor:
(2cos(x)-1)(cos(x)+1) = 0
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cos(x) = 1/2 or cos(x) = -1
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x = +-pi/3 or x = pi
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Cheers,
Stan H.
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