SOLUTION: help me solve plz. the longest side of a right triangle is 1 ft longer than two times the length of the shortest side. the other side of the trinagle is 1 ft shorter than two time

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: help me solve plz. the longest side of a right triangle is 1 ft longer than two times the length of the shortest side. the other side of the trinagle is 1 ft shorter than two time      Log On


   



Question 869612: help me solve plz.
the longest side of a right triangle is 1 ft longer than two times the length of the shortest side. the other side of the trinagle is 1 ft shorter than two times the lengh of the shortest side. Find the lengths of the sides of the triangle.
the length of the shortest side
the length of the other side
the length of the longest side

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
the longest side of a right triangle is 1 ft longer than two times the length of the shortest side. the other side of the triangle is 1 ft shorter than two times the length of the shortest side. Find the lengths of the sides of the triangle.
the length of the shortest side
the length of the other side
the length of the longest side
***
let x=length of the shortest side
2x+1=length of the longest side (hypotenuse)
2x-1=length of the remaining side.
...
By the pythagorean theorem:
x^2+(2x-1)^2=(2x+1)^2
x^2+4x^2-4x+1=4x^2+4x+1
x^2-8x=0
x(x-8)=0
x=0
or
x=8
2x+1=17
2x-1=15
length of the shortest side=8
length of the longest side (hypotenuse)=17
length of the remaining side=15