SOLUTION: I have to solve 3cosx = cosx -1 in the interval 0≤x<2π
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Question 869271
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I have to solve 3cosx = cosx -1 in the interval 0≤x<2π
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lwsshak3(11628)
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solve 3cosx = cosx -1 in the interval 0≤x<2π
3cosx = cosx -1
2cosx = -1
cos x=-1/2
x=5π/6, 7π/6 (In quadrants II and III in which cos<0)