SOLUTION: you have a piggy bank containing a total of 84 coins in dimes and quarters. If the piggy bank contains $16.05, how many dimes are there in the piggy bank?

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Question 869166: you have a piggy bank containing a total of 84 coins in dimes and quarters. If the piggy bank contains $16.05, how many dimes are there in the piggy bank?
Answer by XilliX(3) About Me  (Show Source):
You can put this solution on YOUR website!
Let's say we represent the number of dimes by d and the number of quarters by q


We now that the total number should add up to 84, which can be written like

d+%2B+q+=84 (1)


Additionally we know that
  - 1 dime values 10 cents
  - 1 quarter values 25 cents
  - the total value of our piggy back is 16,05 dollar or 1605 cents

So we can write:

  10d+%2B+25q+=+1605 (2)


This gives us 2 equations (1) and (2).

Equation (1) can be rewritten like so:

  d=84-q

Substituting this into equation (2) gives:

  %2884-q%29%2A10+%2B+25q=1605

  840-10q+%2B+25q=1605

  15q=1605-840

  q=%281605-840%29%2F15
  q=51


Using this value in equation (1) gives us the number of dimes:

  d=84-q -> d=84-51=33

So there are 51 quarters and 33 dimes in the piggy back.

Check:
  51 quarters + 33 dimes = 84 coins
  with a total value of 51 x 25 cents + 33 x 10 cents = 1605 cents = 16,05 dollar