SOLUTION: solve for the value of x in (Inx)^2=Inx^2 is it x=1 or 2?

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Question 86909: solve for the value of x in (Inx)^2=Inx^2
is it x=1 or 2?
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
%28ln%28+x+%29%29%5E2+=+ln%28+x%5E2+%29
e%5E%28ln%28+x+%29%29%5E2+=+x%5E2
e%5E%28ln%28+x+%29%2Aln%28+x+%29%29+=+x%5E2
%28e%5Eln%28+x+%29%29%5Eln%28+x+%29+=+x%5E2
x%5Eln%28+x+%29+=+x%5E2
ln%28+x+%29+=+2
x+=+e%5E2
Simple Way:
%28ln%28+x+%29%29%5E2+=+ln%28+x%5E2+%29
ln%28+x+%29%2Aln%28+x+%29+=+ln%28+x%5E2+%29
ln%28+x%5E%28+ln%28+x+%29+%29%29+=+ln%28+x%5E2+%29
x%5E%28+ln%28+x+%29+%29+=+x%5E2
ln%28+x+%29+=+2
x+=+e%5E2
~Complete Solution~
%28ln%28+x+%29%29%5E2+=+ln%28+x%5E2+%29
%28ln%28+x+%29%29%5E2+=+2%2Aln%28+x+%29
ln%28+x+%29%5E2+-+2%2Aln%28+x+%29+=+0 Substitute: u = ln( x )
u%5E2+-+2%2Au+=+0
u%28u+-+2%29+=+0
u = 0 and u - 2 = 0
u = 0 and u = 2
ln( x ) = 0 and ln( x ) = 2
x = 1 and x = e^2
graph%28400%2C200%2C-2%2C8%2C-5%2C5%2C%28ln%28+x+%29%29%5E2%2Cln%28+x%5E2+%29%29