SOLUTION: A chemist needs 600 milliliters of a 31% alcolol solution. To obtain this solution, how much of a 10% alcohol solution should be mixed with a 40% alcohol solution?

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Question 869081: A chemist needs 600 milliliters of a 31% alcolol solution. To obtain this solution, how much of a 10% alcohol solution should be mixed with a 40% alcohol solution?
Answer by josgarithmetic(39623) (Show Source):
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A chemist needs 600 milliliters of a 31% alcolol solution. To obtain this solution, how much of a 10% alcohol solution should be mixed with a 40% alcohol solution?

More generally, A chemist needs M milliliters of a T% alcolol solution. To obtain this solution, how much of a L% alcohol solution should be mixed with a H% alcohol solution?

Let u = how much of the L% material
Let v = how much of the H% material

and

The solution is fully shown here: Mixing two concentrations for known amount of mixture