SOLUTION: This is actually in preperation for a test on this chapter. I don't understand graphing and sloping real well. It's not the artithmatic that's the problem for me, it's remembering

Algebra ->  Graphs -> SOLUTION: This is actually in preperation for a test on this chapter. I don't understand graphing and sloping real well. It's not the artithmatic that's the problem for me, it's remembering       Log On


   

Question 86893This question is from textbook
: This is actually in preperation for a test on this chapter. I don't understand graphing and sloping real well. It's not the artithmatic that's the problem for me, it's remembering the formulas (step by step.
Here's an example:
Find the slope and the y-intercept of the line given by 4x-9y=15.
Can I get a step-by-step on how to solve this?
Thanx
 This question is from textbook

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Converting Linear Equations in Standard form to Slope-Intercept Form (and vice versa)
Convert from standard form (Ax+By = C) to slope-intercept form (y = mx+b)


4x-9y=15 Start with the given equation


4x-9y-4x=15-4x Subtract 4x from both sides


-9y=-4x%2B15 Simplify


%28-9y%29%2F%28-9%29=%28-4x%2B15%29%2F%28-9%29 Divide both sides by -9 to isolate y


y+=+%28-4x%29%2F%28-9%29%2B%2815%29%2F%28-9%29 Break up the fraction on the right hand side


y+=+%284%2F9%29x-5%2F3 Reduce and simplify


The original equation 4x-9y=15 (standard form) is equivalent to y+=+%284%2F9%29x-5%2F3 (slope-intercept form)


The equation y+=+%284%2F9%29x-5%2F3 is in the form y=mx%2Bb where m=4%2F9 is the slope and b=-5%2F3 is the y intercept.