SOLUTION: Please help me. A CUBE OF ICE 3FT BY 3FT BY 3FT. THE ICE MELTS UNTIL IT BECOMES A CUBE WHICH IS ONE HALF AS HEAVY AS THE ORIGINAL. FIND THE DIMENSION OF NEW CUBE. (DENSITY OF ICE=6
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-> SOLUTION: Please help me. A CUBE OF ICE 3FT BY 3FT BY 3FT. THE ICE MELTS UNTIL IT BECOMES A CUBE WHICH IS ONE HALF AS HEAVY AS THE ORIGINAL. FIND THE DIMENSION OF NEW CUBE. (DENSITY OF ICE=6
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Question 868880: Please help me. A CUBE OF ICE 3FT BY 3FT BY 3FT. THE ICE MELTS UNTIL IT BECOMES A CUBE WHICH IS ONE HALF AS HEAVY AS THE ORIGINAL. FIND THE DIMENSION OF NEW CUBE. (DENSITY OF ICE=62LB/CUB. FT Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! the volume of cube is 27 cu.ft
weight = 62*27=1674 lb
half the weight =1674/2=837 lb
V=Mass/density
V=837/62
=13.5 cu.ft
volume of cube= s^3
s^3=13.5
s= cuberoot of 13.5 = 2.38 ft
