Question 868717: I need help in figuring out how to graph the following function:
f(x)=square root of x+2 and to find the domain, range and to find the interval on which f is increasing, is decreasing, or is constant
Here's what I did:
I set up a table and I used 1,2,3,4 as the value of x. Then I plugged those values into the function to get the values for f(x) and got:
for x=1 -- I got f(x)= square root of 3 or 1.7 --- (square root of 1+2 = square root of 3)
for x=2 -- I got f(x)= square root of 4 or 2 --- (square root of 2+2 = square root of 4)
for x=3 -- I got f(x)= square root of 5 or 2.2 --- (square root of 3+2 = square root of 5)
for x=4 -- I got f(x)= square root of 6 or 2.4 --- (square root of 4+2 = square root of 6)
Then I plotted my graph based on those points with a range of [1.7, infinity)
and a domain of [1, infinity). The text says that my graph, range and domain are incorrect. The text says that the domain is [-2, infinity) and the range is [0, infinity). I need to know how they got that domain and range and how to plot the points for the graph.
Any help would be greatly appreciated.
Thanks
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! I need help in figuring out how to graph the following function:
f(x)=square root of x+2 and to find the domain, range and to find the interval on which f is increasing, is decreasing, or is constant
Here's what I did:
I set up a table and I used 1,2,3,4 as the value of x. Then I plugged those values into the function to get the values for f(x) and got:
for x=1 -- I got f(x)= square root of 3 or 1.7 --- (square root of 1+2 = square root of 3)
for x=2 -- I got f(x)= square root of 4 or 2 --- (square root of 2+2 = square root of 4)
for x=3 -- I got f(x)= square root of 5 or 2.2 --- (square root of 3+2 = square root of 5)
for x=4 -- I got f(x)= square root of 6 or 2.4 --- (square root of 4+2 = square root of 6)
Then I plotted my graph based on those points with a range of [1.7, infinity)
and a domain of [1, infinity). The text says that my graph, range and domain are incorrect. The text says that the domain is [-2, infinity) and the range is [0, infinity). I need to know how they got that domain and range and how to plot the points for the graph.
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f(x) = sqrt(x+2)
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Domain ?
Solve x+2 >= 0
x >= -2
That is the Domain
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Range:: [0,+oo)
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Graph::
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Cheers,
Stan H.
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