SOLUTION: A wheel of fortune contains the integers 1 to 100, inclusive. Two people play against each other. One player wins if the wheel lands on a multiple of either 3 or 7, and the other p

Algebra ->  Probability-and-statistics -> SOLUTION: A wheel of fortune contains the integers 1 to 100, inclusive. Two people play against each other. One player wins if the wheel lands on a multiple of either 3 or 7, and the other p      Log On


   

Question 868496: A wheel of fortune contains the integers 1 to 100, inclusive. Two people play against each other. One player wins if the wheel lands on a multiple of either 3 or 7, and the other player wins if it lands on a multiple of 4 or 6. If neither player wins, the house takes both bets. What's the probability that the house wins?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
There are 33 multiples of 3 from 1 to 100.
There are 25 multiples of 4 from 1 to 100.
There are 16 multiples of 6 from 1 to 100.
There are 14 multiples of 7 from 1 to 100.
That means 33%2B25%2B16%2B14=88 outcomes are wins for the players.
So 12 outcomes are wins for the house.
P%28House+win%29=12%2F100=3%2F25
If I was you, I'd choose 3 or 7.