SOLUTION: how many three digit number can be formed using all the available digits (0-9) such that number starts with an odd number and ends with even number if repetition is allowed.

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Question 868459: how many three digit number can be formed using all the available digits (0-9) such that number starts with an odd number and ends with even number if repetition is allowed.

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Odd digits - 5 of them
Even digits - 5 of them
N=5%2A10%2A5
N=250