SOLUTION: domain of y= sqrt(x-1)+sqrt(6-x)

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Question 868424: domain of y= sqrt(x-1)+sqrt(6-x)
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
You cannot have a negative in the square root. So the radicands must be 0 or positive.


That means,


x-1%3E=0


x-1%2B1%3E=0%2B1


x%3E=1


AND it also means


6-x%3E=0


6-x%2Bx%3E=0%2Bx


6%3E=x


x%3C=6


We found that x%3E=1 AND x%3C=6


So put together, the restrictions on x are 1%3C=x%3C=6 (basically, x is between 1 and 6 including both endpoints)


The domain is the set of x values such that 1%3C=x%3C=6


In interval notation, the domain is [1,6]