SOLUTION: How many pounds of $1.20 per pound nut mixture must be mixed with two pounds of 90c per pound mixture to produce a mixture that sells for $1.00 per pound?

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Question 868407: How many pounds of $1.20 per pound nut mixture must be mixed with two pounds of 90c per pound mixture to produce a mixture that sells for $1.00 per pound?
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
Yes, this is a mixture problem and the concentration unit is dollars per pound.

Let h = the pounds of the higher priced nuts to add.

Accounting for poundage: h+2,... we do not know what its value is but we can use the expression.

Accounting for money: highlight_green%28%281.2%29h%2B%280.9%29%2A2=%281.0%29%28h%2B2%29%29. The equation could also be first formed as its equivalent rational equation, but your first step might be to transform into this green-highlited form here. Notice that 90 cents is 0.90 dollars.

The only variable is h. Solve for h.