SOLUTION: how do you solve the following?
log3x = log4 + log (x-1)
log of base 8 of x^2 = log of base 8 (3x+4)
What numbers do you use to fill in for the varriables?:
A=P{1+r/n}^nt
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-> SOLUTION: how do you solve the following?
log3x = log4 + log (x-1)
log of base 8 of x^2 = log of base 8 (3x+4)
What numbers do you use to fill in for the varriables?:
A=P{1+r/n}^nt
Log On
Question 868250: how do you solve the following?
log3x = log4 + log (x-1)
log of base 8 of x^2 = log of base 8 (3x+4)
What numbers do you use to fill in for the varriables?:
A=P{1+r/n}^nt
ex. Laura borrows $2500 at a rate of 10.5% compounded monthly. Find how much Laura owes at the end of 4 years.
I am studying for a quiz tomorrow and cannot get ahold of any classmates for help. Thanks.
Hi
3x = 4x-4
-x = -4, x = 4
A=P{1+r/n}^nt
A = Accumulated Amount
P= principal =
r= annual rate = .
n= periods per year =
t= years =
A = 2500(1+ .105/12)^48
A = 2500(1.00875)^48 = $3,797.96
