You can put this solution on YOUR website! find cos(theta) given cot(theta)=-0.7 and cos(theta)< 0
cos(theta)=-0.7=-7/10=cos(theta)/sin(theta)
hypotenuse of reference right triangle in quadrant II=√(7^2+10^2)=√49+100=√149
cos(theta)=-7/√149=-7√149/149