SOLUTION: If sinθ=3/8 and θ is in the first quadrant, what is sin2θ. Include a diagram
Please help as my friends and I have been stumped on this one. I know that for the di
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-> SOLUTION: If sinθ=3/8 and θ is in the first quadrant, what is sin2θ. Include a diagram
Please help as my friends and I have been stumped on this one. I know that for the di
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Question 867967: If sinθ=3/8 and θ is in the first quadrant, what is sin2θ. Include a diagram
Please help as my friends and I have been stumped on this one. I know that for the diagram, the missing side is simply:
8^2-3^2=x^2
64-9= x^2
55= x^2
Sqrt55=x
7.4162=x
We've also tried using double angle Identity and got as far as:
sin(2x)=2(3/8)cosx
sin(2x)=2(3/8)(7.1462/8)
sin(2x)=2(3)(7.1562)/64
before realizing we might be wrong.
Also please help with the diagramming as well if you can, since we're also trying to figure out if the numbers from sinθ double in it. (i.e. hypotenuse times 2, etc)
Thanks!