You can put this solution on YOUR website! 2costheta=5+6/costheta
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Multiply thru by cos(t) to get:
2cos^2(t) = 5cos(t) + 6
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2cos^2(t) - 5cos(t) - 6 = 0
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Use the quadratic formula to get:
cos(t) = [5 +- sqrt(25-4*2*-6)]/4
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cos(t) = [5 +- sqrt(73)]/4
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cos(t) = [5+- 8.54]/4
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cos(t) = 3.39 or cos(t) = -0.885
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t = arccos(-0.885) = 152.25 deg in QII
OR
t = arccos(-0.885) = 207.75 deg in QIII
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Cheers,
Stan H.
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