SOLUTION: Find the equation of a hyperbola with a vertex at (-2,15) , a focus at (-2,22) and a center at (-2,7)

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Question 867669: Find the equation of a hyperbola with a vertex at (-2,15) , a focus at (-2,22) and a center at (-2,7)
Answer by lwsshak3(11628) About Me  (Show Source):
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Find the equation of a hyperbola with a vertex at (-2,15) , a focus at (-2,22) and a center at (-2,7)
Given data shows hyperbola has a vertical transverse axis.
Its standard form of equation: %28y-k%29%5E2%2Fa%5E2-%28x-h%29%5E2%2Fb%5E2=1, (h,k)=coordinates of center
center:(-2,7)
a=8 (distance from center to vertices on the vertical transverse axis)
a^2=64
c=15 (distance from center to foci on the vertical transverse axis)
c^2=225
c^2=a^2+b^2
b^2=c^2-a^2=225-64=161
equation of given hyperbola: %28y-7%29%5E2%2F64-%28x%2B2%29%5E2%2F161=1