SOLUTION: Solve for t in the interval [0, 2pi) cos^2(t)-sin^2(t)=0

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Question 867594: Solve for t in the interval [0, 2pi)
cos^2(t)-sin^2(t)=0
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for t in the interval [0, 2pi)
cos^2(t)-sin^2(t)=0
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cos(2t) = 0
2t = pi/2 or 2t = (3/2)t
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t = pi/4 or t = (3/4)t
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Cheers,
Stan H.====================