SOLUTION: Hi there, I have a question pertaining to solving exponential equations with common bases. I understand the whole when bases are equal the exponents must be equal, but I don't quit

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Hi there, I have a question pertaining to solving exponential equations with common bases. I understand the whole when bases are equal the exponents must be equal, but I don't quit      Log On


   

Question 867503: Hi there, I have a question pertaining to solving exponential equations with common bases. I understand the whole when bases are equal the exponents must be equal, but I don't quite get how to solve so the exponents are equal.
For example
3^2x+6 = 3^-3
They have the same bases so all I've got to do is solve:
2x+6 = -3
And it becomes 2X = -9. I don't understand how you get 2x = -9,
, and then x = -9/2.
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
another way
3^(2x+6) = 3^-3
3^(2(x+3)) = 3^-3
2(x+3)=-3
x+3=-3/2
x=-3/2-3
x=-9/2