SOLUTION: Hi tutor, I know that it's already 1.50 am (depending on which country you're at), But could you please help me solve this?? I've attempted it but I still couldn't get the answer.

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Hi tutor, I know that it's already 1.50 am (depending on which country you're at), But could you please help me solve this?? I've attempted it but I still couldn't get the answer.       Log On


   

Question 867475: Hi tutor, I know that it's already 1.50 am (depending on which country you're at), But could you please help me solve this?? I've attempted it but I still couldn't get the answer.
If log[5]2=x, show that log[2]=x/x+1.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
If log[5]2=x, show that log[2]=x/x+1.
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x+=+log%285%2C2%29
x%2B1+=+log%285%2C2%29+%2B+log%285%2C5%29+=+log%285%2C10%29
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x%2F%28x%2B1%29+=+log%285%2C2%29%2Flog%285%2C10%29
= %28log%282%29%2Flog%285%29%29%2F%28log%2810%29%2Flog%285%29%29
= log(2)/log(10) = log(2)/1
= log(2)