Question 867364: a certain confidence interval is 8.95 < u < 10.25. Find the sample mean and margin of error
Answer by jim_thompson5910(35256)   (Show Source):
You can put this solution on YOUR website! To find the sample mean (xbar) of any confidence interval (L,U), we use the formula below
xbar = (U + L)/2
Plug in the given values L = 8.95 and U = 10.25 and then evaluate
xbar = (U + L)/2
xbar = (10.25 + 8.95)/2
xbar = 9.6
So the sample mean is 9.6
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To find the margin of error (ME) of any confidence interval (L,U), we use the formula below
ME = (U - L)/2
Plug in the given values L = 8.95 and U = 10.25 and then evaluate
ME = (U - L)/2
ME = (10.25 - 8.95)/2
ME = 0.65
The margin of error is 0.65
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