SOLUTION: x=-4(+-)√(4^2-4*1*5)/(2*1)=(-4(+-)√-4)/2=(-4(+-)√-4)/2=(-4(+-)2i)/2=-2(+-)i This is wrong What went wrong? What is the correct answer?

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: x=-4(+-)√(4^2-4*1*5)/(2*1)=(-4(+-)√-4)/2=(-4(+-)√-4)/2=(-4(+-)2i)/2=-2(+-)i This is wrong What went wrong? What is the correct answer?      Log On


   

Question 867147: x=-4(+-)√(4^2-4*1*5)/(2*1)=(-4(+-)√-4)/2=(-4(+-)√-4)/2=(-4(+-)2i)/2=-2(+-)i
This is wrong
What went wrong?
What is the correct answer?
Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
from your work
(-4 + or - square root (-4)) / 2
(-4 + or - 2i) / 2
2(-2 + or - i) / 2
x = -2 + i = -(2 - i)
x = -2 - i = -(2 + i)