SOLUTION: I am stuck on homework due in 1 hour, please help solve. x=(y+2)^2 1. Show the five points of the graph and how you got them. 2. what are the start/end points? 3. what is t

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: I am stuck on homework due in 1 hour, please help solve. x=(y+2)^2 1. Show the five points of the graph and how you got them. 2. what are the start/end points? 3. what is t      Log On


   

Question 867079: I am stuck on homework due in 1 hour, please help solve.
x=(y+2)^2
1. Show the five points of the graph and how you got them.
2. what are the start/end points?
3. what is the general shape and location of the graph?
4. State the domain and range for equation in interval notation.
5. State whether the equation is a function or not giving your reason why.
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Given equation highlight_green%28x=%28y%2B2%29%5E2%29

1. Show the five points of the graph and how you got them.

What five points? The graph of the equation has infinite number of points.

2. what are the start/end points?

What do you mean? This graph has a vertex on the left and infinite number of points to the right.

3. what is the general shape and location of the graph?

The equation is in standard form for a parabola with a horizontal axis of symmetry. The parabola opens toward the right and the vertex (based on knowing how to read from the standard form equation) is (0, -2). The graph is symmetric around y=-2.
4. State the domain and range for equation in interval notation.

The point farthest to the left is (0, -2). The graph and equation are of TWO separate functions. The domain for each branch is 0%3C=x ( using inequality relationship notation, and not as you asked in interval notation ). The range for the upper branch is y%3E=-2 and the range for the lower branch is y%3C=-2.

5. State whether the equation is a function or not giving your reason why.

The equation is NOT a function. Try the "Vertical Line Test". What does it tell you? Look at any value of x in the domain of y=%28x%2B2%29%5E2. If you find more than one value for y for ANY value of x, then the relation is not a function. A function must have no more than one value for output for any input.