SOLUTION: The perimeter of a rectangle is 80 feet. Find the dimensions if the length is 5 feet longer than four times the width. Then find the area of the rectangle.

Algebra ->  Rectangles -> SOLUTION: The perimeter of a rectangle is 80 feet. Find the dimensions if the length is 5 feet longer than four times the width. Then find the area of the rectangle.       Log On


   

Question 867052: The perimeter of a rectangle is 80 feet. Find the dimensions if the length is 5 feet longer than four times the width. Then find the area of the rectangle.

Answer by josgarithmetic(39626) About Me  (Show Source):
You can put this solution on YOUR website!
w and L;
L=3w+5;
2w%2B2%283w%2B5%29=80
8w%2B10=80
4w%2B5=40
4w=35
highlight%28w=35%2F4%29
-
L=3%2835%2F4%29%2B5%284%2F4%29
L=%28105%2B20%29%2F4
highlight%28L=125%2F4%29
-
The dimension sizes kept in improper fraction form for ease in calculating the requested area.
-
AREA, wL=%2835%2F4%29%28125%2F4%29=highlight%284375%2F16%29
Or
highlight%28273%267%2F16%29 square feet.