SOLUTION: x^2+2x-8 divided by -x^3-2x^2-24x my teacher wants me to simplify it then factor it out and tell her what x cannot be. so far I factored the top one.. I believe it is (x+4)(x-2)

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Question 867026: x^2+2x-8 divided by -x^3-2x^2-24x
my teacher wants me to simplify it then factor it out and tell her what x cannot be.
so far I factored the top one.. I believe it is
(x+4)(x-2)
but I do not know how to solve the bottom because it is cubed..

Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website!
x^2+2x-8 divided by -x^3-2x^2-24x
my teacher wants me to simplify it then factor it out and tell her what x cannot be.
so far I factored the top one.. I believe it is
(x+4)(x-2)
but I do not know how to solve the bottom because it is cubed..
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You don't solve the bottom, you factor it.
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-x^3-2x^2-24x
Factor out (or divide by) -x
= -x*(x^2 + 2x + 12)
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x cannot be a value that makes the DEN (bottom) = 0
So x <> 0
------
The other 2 x's are complex numbers, not real.
I don't know if you want those.
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

The discriminant -44 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.

In the field of imaginary numbers, the square root of -44 is + or - .

The solution is , or
Here's your graph:

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