SOLUTION: find the value of theta in 6 sin^2 theta + 7 cos theta - 7 = 0

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Question 866939: find the value of theta in
6 sin^2 theta + 7 cos theta - 7 = 0
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
6sin%5E2%28theta%29+%2B+7cos%28theta%29+-+7+=+0
6%2A%281-cos%5E2%28theta%29%29+%2B+7cos%28theta%29+-+7+=+0
6-6cos%5E2%28theta%29%2B7cos%28theta%29-7=0
-6cos%5E2%28theta%29%2B7cos%28theta%29-1=0
6cos%5E2%28theta%29-7cos%28theta%29%2B1=0
cos%28theta%29-1%29%286cos%28%28theta%29-1%29%29=0
Two solutions:
cos%28theta%29=1
theta=0
and
6cos%28theta%29-1=0
6cos%28theta%29=1
cos%28theta%29=1%2F6
theta=80.4 and theta=279.6