what is the question?
Hi
p(lh) = .15, n = 29
a) Compute the probability that exactly five students are left-handed.
P(x = 3) = binompdf(29, .15, 3) = .180
(b) Compute the probability that at most four students are left-handed.
P(x ≤ 4) = binomcdf(29, .15, 4)= .555
(c) Compute the probability that at least six students are left-handed.
P(x ≥ 3) = 1 - binomcdf(29, .14, 2) = .832