SOLUTION: a straight line with equation 2y = kx + h passes through the points (-3,6) and ( 1,11) find the value of k and of h

Algebra ->  Coordinate-system -> SOLUTION: a straight line with equation 2y = kx + h passes through the points (-3,6) and ( 1,11) find the value of k and of h       Log On


   

Question 866746: a straight line with equation 2y = kx + h passes through the points (-3,6) and ( 1,11) find the value of k and of h
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
+2y+=+kx+%2B+h
2%286%29+=+k%28-3%29+%2B+h
1.-3k%2Bh=12
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+2y+=+kx+%2B+h
2%2811%29=k%281%29%2Bh
2.k%2Bh=22
Subtract eq. 2 from eq. 1,
-3k%2Bh-k-h=12-22
-4k=-10
k=10%2F4
k=5%2F2
Then use either equation to solve for h
5%2F2%2Bh=22
h=44%2F2-5%2F2
h=39%2F2