SOLUTION: For the following question I need the standard parabola equation solved for Y. (y-4)^2=2(x+11) THANK YOU!

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Question 866690: For the following question I need the standard parabola equation solved for Y.
(y-4)^2=2(x+11)
THANK YOU!
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
That would not be a standard equation for y for a parabola. How about standard form for x in terms of y instead? Your given equation has the square for y already completed and only x in the power of 1, so standard form as x in terms of y is possible.

You can solve your equation for y in terms of x, but it will not be a standard form parabola equation.
%28y-4%29%5E2=2%28x%2B11%29
y-4=0%2B-+sqrt%282%28x%2B11%29%29
y=4%2B-+sqrt%282%28x%2B11%29%29
highlight%28y=4%2B-+sqrt%282%29sqrt%28x%2B11%29%29, two square root functions, each being half a parabola. Each is stretched horizontally, and vertex is (-11,4); axis of symmetry between the two functions is y=4.