SOLUTION: I need some help on this volume problem. You are going to put a pyramid shape trophy in a box with the same dimensions. The dimensions are 5', 5', and 9'. What is the volume of the

Algebra ->  Volume -> SOLUTION: I need some help on this volume problem. You are going to put a pyramid shape trophy in a box with the same dimensions. The dimensions are 5', 5', and 9'. What is the volume of the      Log On


   

Question 866566: I need some help on this volume problem. You are going to put a pyramid shape trophy in a box with the same dimensions. The dimensions are 5', 5', and 9'. What is the volume of the left over empty space?
Hope you can help! Thanks!
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
The connection with pyramids and rectangular prisms (ie "boxes") is this


(Volume of Pyramid) = (1/3)*(Volume of Rectangular Prism)


Note: This equation is true if they both have the same base area and same height.


The box or rectangular prism has a volume of V = L*W*H = 5*5*9 = 225 cubic feet.


So the pyramid has a volume of 1/3 of that, equal to (1/3)*225 = 75 cubic feet.


The amount of empty space is equal to the difference of the two: 225-75 = 150


The volume of empty space is 150 cubic feet