SOLUTION: Three fair quarters and an unfair quarter with two heads are placed in a bag. One quarter is selected, and tossed. What is the probability of getting "heads"? THANK YOU SO

Algebra ->  Probability-and-statistics -> SOLUTION: Three fair quarters and an unfair quarter with two heads are placed in a bag. One quarter is selected, and tossed. What is the probability of getting "heads"? THANK YOU SO       Log On


   

Question 866440: Three fair quarters and an unfair quarter with two heads are placed in a bag. One quarter is selected, and tossed.
What is the probability of getting "heads"?
THANK YOU SO MUCH FOR HELPING ME!
Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
P(heads) = P(fair quarter)*P(heads|fair quarter) + P(unfair quarter)*P(heads|unfair quarter)

= (3/4)*(1/2) + (1/4)*1

= 5/8