SOLUTION: If sin[theta]= 3/8 what does sec[theta]+tan[theta] equal? Am I on the right track? Sin[theta]= y/r (x)^2= (8)^2-(3)^2 x= square root of 55...

Algebra ->  Trigonometry-basics -> SOLUTION: If sin[theta]= 3/8 what does sec[theta]+tan[theta] equal? Am I on the right track? Sin[theta]= y/r (x)^2= (8)^2-(3)^2 x= square root of 55...       Log On


   

Question 866409: If sin[theta]= 3/8
what does sec[theta]+tan[theta] equal?
Am I on the right track?
Sin[theta]= y/r
(x)^2= (8)^2-(3)^2
x= square root of 55...

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
If sin[theta]= 3/8
what does sec[theta]+tan[theta] equal?
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use x for theta:
sinx=3/8
cosx=√(1-sin^2x)=√(1-9/64)=√(55/64)=√55/8
secx=1/cosx=8/√55
tanx=sinx/cosx=3/√55
secx+tanx=(8/√55)+(3/√55)=11/√55