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Question 866260: OK, I think that I got this right but I would like a double check please.
Set up an augmented matrix and use the Gaussian elimination method to solve each system.
x+2y+2z=6
2x-y+z=0
-x+y-2z=3
I got x=2, y=3, and z=-1
Thank you in advance for any help received.
Answer by richwmiller(17219)   (Show Source):
You can put this solution on YOUR website! x = 2, y = 3, z = -1
Add (-2 * row1) to row2
1 2 2 6
0 -5 -3 -12
-1 1 -2 3
Add (1 * row1) to row3
1 2 2 6
0 -5 -3 -12
0 3 0 9
Divide row2 by -5
1 2 2 6
0 1 3/5 12/5
0 3 0 9
Add (-3 * row2) to row3
1 2 2 6
0 1 3/5 12/5
0 0 -9/5 9/5
Divide row3 by -9/5
1 2 2 6
0 1 3/5 12/5
0 0 1 -1
Add (-3/5 * row3) to row2
1 2 2 6
0 1 0 3
0 0 1 -1
Add (-2 * row3) to row1
1 2 0 8
0 1 0 3
0 0 1 -1
Add (-2 * row2) to row1
1 0 0 2
0 1 0 3
0 0 1 -1
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