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| Question 866140:  A family has 4 children. Using a tree diagram that shows how many ways the children could have been born, from first to last born, determine how many ways the family could have had 2 boys and 2 girls. Then find the probability of having 2 boys and 2 girls.
 Answer by jim_thompson5910(35256)
      (Show Source): 
You can put this solution on YOUR website! Here is a tree diagram depicting all the possible ways to have 4 kids 
 
   
 The first column (of just 2 choices) represents child #1.
 
 
 If we stop at the second column, and ignore everything past it, then we see that there are 2^2 = 4 ways to have 2 kids (and those ways are shown in the tree diagram)
 
 
 Likewise, if we stop at column #3, then we see all the possible ways to have 3 kids (2^3 = 8 different ways)
 
 
 The last column is that last and 4th child. There are 2^4 = 16 ways to have 4 kids. Each possible path you trace (from the starting node to either a B or G in the fourth column) generates a sequence of 4 letters (either B or G) that represents a combination of boys and/or girls. For example, trace along the very top branches and you'll only pick up B, B, B, B or BBBB which represents all 4 kids being boys.
 
 
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 Let's highlight all of the paths that have exactly 2 boys and exactly 2 girls.
 
 
 Here is one path
 
 
   
 This is the sequence BBGG which means the first two kids are boys, the second 2 are girls (boy, boy, girl, girl)
 
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 Here is another
 
 
   
 
 That is the sequence BGBG (boy, girl, boy, girl)
 
 
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 Here is another
 
 
   
 
 This sequence is BGGB (boy, girl, girl, boy)
 
 
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 and here is another path of exactly 2 girls, 2 boys
 
 
   
 This sequence is GBBG (girl, boy, boy, girl)
 
 
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 and here is another path of exactly 2 girls, 2 boys
 
 
   
 
 This sequence is GBGB (girl, boy, girl, boy)
 
 
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 and finally, here is the last path that represents exactly 2 girls, 2 boys
 
 
   
 This sequence is GGBB (girl, girl, boy, boy)
 
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 There are 6 sequences highlighted above and they are
 
 BBGG
 BGBG
 BGGB
 GBBG
 GBGB
 GGBB
 
 So there are 6 ways to have 2 boys and 2 girls (they are shown above).
 
 
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 To calculate the probability of having 2 boys and 2 girls, you divide that last number we found (6) by 16. This is because there are 16 ways to have 4 kids (2^4 = 16)
 
 
 So,
   
 
 The answer as a fraction is
   
 
 Now use a calculator to get
   
 
 The answer as a decimal is 0.375
 
 
 And multiply that decimal result by 100 to convert it over to a percentage 0.375*100 = 37.5%
 
 
 The answer as a percentage is 37.5%
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