SOLUTION: Factor and solve: 2x^5+4x^4-4x^3-8x^2=0
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Algebra: Distributive, associative, commutative properties, FOIL
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Question 866084
:
Factor and solve:
2x^5+4x^4-4x^3-8x^2=0
Answer by
richwmiller(17219)
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2x^2 *(x^3+2x^2-2x-4) = 0
2x^2 *(x+2)* (x^2-2) = 0
