SOLUTION: Hello! I would like to know how to solve for x in this log problem.
log(2x+5) * log(9x^2) = 0
This problem should have 3 solutions: -2, -1/3, +1/3.
Please help me. Thank y
Algebra ->
Exponential-and-logarithmic-functions
-> SOLUTION: Hello! I would like to know how to solve for x in this log problem.
log(2x+5) * log(9x^2) = 0
This problem should have 3 solutions: -2, -1/3, +1/3.
Please help me. Thank y
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Question 866073: Hello! I would like to know how to solve for x in this log problem.
log(2x+5) * log(9x^2) = 0
This problem should have 3 solutions: -2, -1/3, +1/3.
Please help me. Thank you! :) Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website! -2, -1/3, +1/3 are correct
The key is log(1)=0
log(2x+5)*log(9x^2) = 0
log(9x^2) = 0
x^2=1/9
x=-1/3
x=+1/3
log(2x+5)=0
2x+5=1
2x=-4
x=-2
