Hi
p(def) = .14, n = 100
P(x = 11) = binompdf(100, .14, 11) = .0849 0r 8.49%
p(def) = .14, n = 15
P(x = 4) = binompdf(15, .14, 4) = .0998 0r 9.98%
Or for singular probability:
Using
p and q are the probabilities of success and failure respectively.
In this case p= .14 and q = .86