SOLUTION: i need help.. so far i have find the product of: 2[a^2+3(a-2)] and 3[a^2+3(a+1)] 2(a^2+3a-6) - then i distribute 2a^2+6a-12 3[a^2+3(a+1)] 3(a^2+3a-3) - then i d

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: i need help.. so far i have find the product of: 2[a^2+3(a-2)] and 3[a^2+3(a+1)] 2(a^2+3a-6) - then i distribute 2a^2+6a-12 3[a^2+3(a+1)] 3(a^2+3a-3) - then i d      Log On


   

Question 865798: i need help.. so far i have
find the product of:
2[a^2+3(a-2)] and 3[a^2+3(a+1)]
2(a^2+3a-6) - then i distribute
2a^2+6a-12

3[a^2+3(a+1)]
3(a^2+3a-3) - then i distribute
3a^2+9a-9
how do i multiply -
2a^2+6a-12
3a^2+9a-9 ?
Found 2 solutions by mananth, josgarithmetic:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
2a^2+6a-12
3a^2+9a-9
%282a%5E2%2B6a-12%29%283a%5E2%2B9a-9%29

%282a%28a%2B3%29-12%29%283a%28a%2B3%29-9%29
put (a+3)=b
(2ab-12)(3ab-9)
6a%5E2b%5E2-18ab-36ab%2B108
6a%5E2b-54ab%2B108
6a%5E2%28a%2B3%29-54a%28a%2B3%29%2B108
6a%5E3%2B18a%5E2-54a%5E2-162a%2B108
6a%5E3-36a%5E2-162a%2B108

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Starting with: 2%28a%5E2%2B3%28a-2%29%29%2A3%28a%5E2%2B3%28a%2B1%29%29
More than one path to simplifying.
2%2A3%28a%5E2%2B3a-6%29%28a%5E2%2B3a%2B3%29
6%28a%5E2%2B3a-6%29%28a%5E2%2B3a%2B3%29

IF you want or must use Distributive property between the two trinomials, you can distribute from the right or from the left, but be consistant.


Simplify the terms inside the parentheses.
6%28a%5E4%2B3a%5E3-6a%5E2%2B3a%5E3%2B9a%5E2-18a%2B3a%5E2%2B9a-18%29
Cleanest general form including combining like-terms inside parentheses...
6%28a%5E4%2B6a%5E3%2B12a%5E2-9a-18%29
highlight%286a%5E4%2B36a%5E3%2B72a%5E2-54a-108%29