SOLUTION: H and M travelled on the same route to Town X. H left his house at 6.15am and travelled at an average speed of 80km/h. 45 minutes later, M left for Town X and travelled at an avera
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Question 865478: H and M travelled on the same route to Town X. H left his house at 6.15am and travelled at an average speed of 80km/h. 45 minutes later, M left for Town X and travelled at an average speed of 100km/h . At what time did they meet on the way ? Answer by dkppathak(439) (Show Source):
You can put this solution on YOUR website! H and M traveled on the same route to Town X. H left his house at 6.15am and traveled at an average speed of 80 km/h. 45 minutes later, M left for Town X and traveled at an average speed of 100km/h . At what time did they meet on the way ?
Answer
distance traveled in 45 minutes by H( As M left 45 minutes later)
= 80 x 45/60= 60 km
M left house at 7 am( 45 minutes later than H ) by the time H traveled 60 KM with
speed of M is 100 km/H
time taken to meet H with difference of 60 km . means M have to traveled 60 km to meet H
time=distance/ speed
= 60/100 hours = 0.6 hours = 0.6 x 60 =36 minutes ( we know 1 hours is equal to 60 minutes )
therefor both will meet after 36 minutes after starting of M
Both will meet at 07:36
