SOLUTION: Please help me solve this problem Solve the equation on the interval 0 < x < 2(pi) Sin^2(x) + sin (x) = 0

Algebra ->  Trigonometry-basics -> SOLUTION: Please help me solve this problem Solve the equation on the interval 0 < x < 2(pi) Sin^2(x) + sin (x) = 0       Log On


   

Question 865399: Please help me solve this problem
Solve the equation on the interval 0 < x < 2(pi)
Sin^2(x) + sin (x) = 0
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
sin^2(x) + sin(x) = 0


sin(x)( sin(x) + 1 ) = 0


sin(x) = 0 or sin(x) + 1 = 0


sin(x) = 0 or sin(x) = -1


x = arcsin(0) or x = arcsin(-1)


x = 0,pi or x = 3pi/2


The three solutions are x = 0, x = pi, x = 3pi/2