SOLUTION: A cable with one end attached to a bucket at the bottom of a mine shaft is being wound around a cylindrical drum 12 feet in diameter which is turning at the rate of 24 rpm. assumin

Click here to see ALL problems on Trigonometry-basics

Question 865352: A cable with one end attached to a bucket at the bottom of a mine shaft is being wound around a cylindrical drum 12 feet in diameter which is turning at the rate of 24 rpm. assuming the hoist is raising the bucket from the bottom of the shaft to the surface in nine minutes and thirty four seconds, calculate the depth of the shaft accurate to the nearest ten feet. (please explain)
Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website!
A cable with one end attached to a bucket at the bottom of a mine shaft is being wound around a cylindrical drum 12 feet in diameter which is turning at the rate of 24 rpm. assuming the hoist is raising the bucket from the bottom of the shaft to the surface in nine minutes and thirty four seconds, calculate the depth of the shaft accurate to the nearest ten feet. (please explain)
If the drum rotates once the bucket will rise by 2*pi*r feet
radius of drum = 6 feet
so circumference = 12 pi
In one minute it makes 24 revolutions
In one minute the bucket will come up by 24 * 12 pi feet

so in 9 mins 34 seconds it will cover ?
9 34/60 = (287/30)
It will cover
=8651.328
= 8651 feet
the depth is 8651 feet