SOLUTION: Find three consecutive positive odd integers such that the product of the first and third is equal to 1 less than twice the second.

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Find three consecutive positive odd integers such that the product of the first and third is equal to 1 less than twice the second.       Log On


   

Question 865327: Find three consecutive positive odd integers such that the product of the first and third is equal to 1 less than twice the second.
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
x*(x+4)=2x+4-1
x^2+4x)=2x+4-1
x^2+2x-3=0
(x+3)*(x-1)
1 3 5
check
1*5=2*3-1
5=5
ok