SOLUTION: the band members sold tickets to their concert performance. some were $3 tickets and some were $8 tickets. there were 10 more than twice as many $8 tickets sold as $3 tickets. the
Algebra ->
Finance
-> SOLUTION: the band members sold tickets to their concert performance. some were $3 tickets and some were $8 tickets. there were 10 more than twice as many $8 tickets sold as $3 tickets. the
Log On
Question 865271: the band members sold tickets to their concert performance. some were $3 tickets and some were $8 tickets. there were 10 more than twice as many $8 tickets sold as $3 tickets. the total sales were $1,448. how many tickets of each price were sold. Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! the band members sold tickets to their concert performance. some were $3 tickets and some were $8 tickets. there were 10 more than twice as many $8 tickets sold as $3 tickets. the total sales were $1,448. how many tickets of each price were sold.
$3 tickets ----------------------x
$8 tickets ----------------------y
y=2x+10
y-2x=10.................(1)
3x+8y=1448...............(2)
solve for x & y
-2 x + 1 y = 10 .............1
Total value
3 x + 8 y = 1448 .............2
Eliminate y
multiply (1)by -8
Multiply (2) by 1
16 x -8 y = -80
3 x + 8 y = 1448
Add the two equations
19 x = 1368
/ 19
x = 72
plug value of x in (1)
-2 x + 1 y = 10
-144 + y = 10
y = 10 + 144
y = 154
y = 154
x= 72 number of $3
y= 154 number of $8
m.ananth@hotmail.ca
