SOLUTION: Hi could i please have help with the question (8ii) in the following link of an exam past question. Thank you
http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%2
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Parallelograms
-> SOLUTION: Hi could i please have help with the question (8ii) in the following link of an exam past question. Thank you
http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%2
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Question 865099: Hi could i please have help with the question (8ii) in the following link of an exam past question. Thank you
http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20%289709%29/9709_w10_qp_13.pdf Answer by KMST(5328) (Show Source):
You can put this solution on YOUR website! You could just use Geometry and Trigonometry.
Because the figure involves a rhombus and arcs of circles with a rhombus side as a radius,
AQ = AB = AD = BC = DC = PC = 5 cm
and angle BAD = 1.2 radians.
AMB is a right triangle, with an angle at A that measures radians.
AM = ABcos(0.6)
PM = MQ = AQ - AM = AB - ABcos(0.6) = AB(1-cos(0.6))
PQ = PM + MQ = 2MQ = 2AB(1-cos(0.6))
Since AB = 5 cm, the length of PQ, in cm, is
