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Question 865024: Find the coordinates of the vertices, foci, and the equations of the asymptotes for the hyperbola 2x^2-y^2=8 State the length of the transverse axis
Answer by richwmiller(17219)   (Show Source):
You can put this solution on YOUR website! semimajor axis length= 2 from center to one vertex
semiminor axis length= 2sqrt(2)
The line going from one vertex, through the center, and ending at the other vertex is called the "transverse" axis. It is twice the semimajor axis length
The distance from the center to each vertex is called the semi-major axis.
The transverse axis is 4
vertices (-2, 0) ; (2, 0)
asymptotes y=sqrt(2)x; y =-sqrt(2)x
foci (-2sqrt(3),0); (2sqrt(3),0)
The line going from one vertex, through the center, and ending at the other vertex is called the "transverse" axis. It is twice the semimajor axis length
The distance from the center to each vertex is called the semi-major axis.
The transverse axis is 4
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